A short bar magnet is placed in the magnetic meridian of the earth with a north pole pointing no....

hello let's read the question question say a short bar magnet is placed in the magnetic Meridian of the Earth with a North Pole pointing North neutral points found at a distance of 30 cm from the magnet on the E Line turn through the middle point of the magnet the Magnetic Moment of the magnet is in amp met square is close to given M 4 Pi = - 7 in SI unit and B is = 3.6 into 10us 5 Tesla fi geographic North and let's say this isographic South mag from South toic South toic sector point

x pular bis sector Point magial upon 4 M upon xal B so [Music] mate 30 into 10^ - 2 whole Cub is = to b or B 3.6 into 10us 5 and solve M = 3.6 into - 5 multiplied by it is 27,000 into 10^ -6 / 10^ - 7 which is equal to 9.7 amp m is square which is the option one I hope you understood the solution thank you