hello B let's read this question the question says 25 ml off an aqua solution of KCl was found to require 20 ml of one mol silver nitrate solution when titrated using a potassium chromate as indicator the pressure and freezing point of KCl solution with 100% ionization will be KF value theity equal toity option a 3. 2 option b have 1. 6 de C option C has 0.
8 de C option b have 5° C the key concept for this question is depression in depression in freezing point look depression in freezing point key basically Delta TF is equal to KF into M Delta TF is equal to KF into M okay now solution I into KF into m i solution disate cus 2 - 2 - 1 into 1 to 1 + N - 1 into Alpha Alp 1 or number of 2us TF is equal to 2 into 2° C mole per K into foral reaction number of moles of K number of mes of ag3 M1 V1 is equal M2 V2 right is basically equals to number of moles of solute by volume of solution right number ofes right into V1 2 25 ml ml mL marity of KCl will be equals to 20 by 20 which is 4X 5 0. 8 mol or mity of KCl 0. 8 mol okay Delta TF is equals to 2 into 2° C mole inverse kg into 0.
8 8 . 8 mole per kg take mo2 Del TF 3.
