good everyone welcome to my channel welcome to med school drill on today's tutorial video we'll be taking multiple choice question under the biochemistry of carbohydrates we're taking 50 mcq question if i will begin kindly subscribe to my channel and i thank you for 100 subscribers i'm very glad this kind of supports so i can always post new videos frequently thank you we are what we repeatedly do excellence then is not an act but a habit so said by aristotle's number one the number of asymmetric carbon atoms in glucose is one ocean b two ocean three c option d four so what is the answer so do not the right answer here is d we have four asymmetric carbon atoms in the glucose molecule four number two beta 1 4 glycosidic bond is present in a motors b lactose c sucrose d none of the above so what's the right answer so the right answer here has to be lactose it's lactose will find a bit alone for glycosidic bond number three number of stereoisomers of glucose is a 2 b 4 c 8 d 16. so what is the answer what do you think is right now in this question the number of stereo isomers of glucose yeah the right answer here is d we have 16 stereoisomers in a glucose molecule sorry number four a homo polysaccharide made up of fructose is a glycogen b dextrine c cellulose d inulin so what answer you should you should know what a homo po saccharide is before you can answer this question the right answer here is now a homo polysaccharide like i just said is uh is a a massive carbohydrate molecule that is made up of the same monomeric unit for instance now you know that prosaccides are made up of large change large um chains of monosaccharides or calcium monomeric units so in this case inulin is made up of fructose multiple billions numbers of fructose molecule but it's only fructose because the word a glycogen molecule sorry a glycoportion in cardiac glycosides is made up of a glucose b steroids c manus d galactose lactose a glucose b steroids c mannose d galactose so the right answer here answer here is b steroids you have steroids in the a glycome portion in cardiac glycosides number six identical ultrasounds are formed by a glucose and fructose b glucose ammonos c manus and fructose d all of the above so by now if you have gotten ones the answer to the right answer here is all of the above they are correct number seven motors can be formed by hydrolysis of a stash b dextrin c glycogen d all of this so what do you believe is the right answer no when when they say hydrolysis like a breaking down of a larger molecule to give you a smaller molecule through the action of water so the right answer here is stash stash is the right answer here number eight alpha one four glycosidic bond is not present in a glycogen b dextrin c amylus d amylopectin so what do you think of the answer you know when i wrote here alpha one says like acidic bond this is why i meant by the alpha this is what the alpha is this is a symbol like this so what you think is the answer here so the right answer here is b the string is right answer here number nine sulfated iodinic acid is present in a higher uronic acid b chonjo weak sulfate c hyperin d all of this so the following will you find sulfated hydronic acid so you'll find this uh in all of them you know them number 10 monosaccharides can be separated by a electrophoresis b chromatography c sorting out the none of this so in what sorry in which of these following methods can monosaccharides be separated from each other so the right answer here is uh chromatography so what they mean here is like this for instance now monosaccharides are being bonded into either a short chain or a long chain so they want to separate them into individual monomeric units so you do that by using a comatographic method of separation number 11 photos is present in hydro listed off a sucrose b inulin c none of this the nader of this so you see both of these d need up this sorry so my level what's right answer be careful those options they are quite tricky remember the two main things we have here is the 10 fructose and the term hydrolysis so the right answer here is c both of them so both sucrose and ignoring are the right answer to this question okay next question number 12 n acetyl galactosamine sulfate is present in higher urinic acid b hyperin d trondo chandra teeth suffered the none of this so without following will you find this particular substance chemical we have here so the right answer here is a challenging surface the word gives me issue to pronounce sometimes but in invertes catalyzes the hydrolysis of a motors b lactose c sucrose d none of this inverters catalyzes the hydrolysis of a motors b lactose c sucrose d none of this the right answer here is sucrose number 14 in fructo ferranos a numeric carbon atom is a carbon 1 b carbon two c carbon three d carbon four okay so what is the right hand side here right right hand side here so the right answer in this question would be carbon two i want to try to answer here remember uh this did this time here fructo they referring to uh fructose why fairness they referring to a um a sugar cyclic chain of just five carbons so it's like a pentagon the the ring like a pentagon why if you see pyramid spanish has six carbons so it'd be like a number 15 a carbohydrate found in dna is a ribose b dioxides c riboluse d all of this so until the following carbohydrates you find in a dna molecule so the right answer here is diagonal ribose the dt in this dna stands for diluted ribose number 16 a monosaccharides having d and l isomer is sorry not having d and l is a ribose b dioxy ribose c electrodes d dihydroxy acetone a monster white not having d and l isomers is ribose b dioxybibles c electrodes d dihydroxy acetone so the right answer this question which you should have gotten by now is d so you're correct i'm sorry d right answer is d no 17. bibolus is a or an a keto pencils what you think is the right answer this question to the right answer is uh ac pentose mean meaning has uh five carbons tetros means she has a five carbon why keto means it has the keto of functional group biotin in the glyceraldehyde o h group is present on the right hand side of carbon atom number dash a 1 b 2 c 3 d 1 or 2 and 3.
so what do you think is the right answer and d glycerade hide the hydroxy or the oh group is present on the right hand side of carbon atom number what's coming from my what a couple other number what that should be so the right answer to this question is number two number 19 a disaccharide made up of two glucose units is a sucrose b motors c lactose d dextrin a dissector is made up of two glucose units is dash is dash dash dash dash so the right answer here is a mole tool to the right answer if you break that multiples by analysis you will definitely have two glucose units number 20 a carbohydrates commonly known as dextrose is a dextrin b fructose c d glucose d glycogen so what is the answer a carbohydrates commonly known as dextrose is dash a the strain b d fructose c d glucose d glycogen so the right answer to number 20 is d glucose now we have d because we have l so the amount they did look around the air glucose the d glucose is more important to the body and it's more is more it's more commonly found in the body than i mean support like that number 21 i amino sugars are present in a highly higher urinic acid b chondroitin sulfate c a vitro myosin d all of the this amino sugars are present in a higher uranic acid b trondo tin sulfate d here your myosin they all of this so right answers all of this you can find my new sugars in all of them from a to c number 22 a carbohydrate found only in milk is a glucose big lactose c lactose d maltose is a very very popular question sometimes asks you what is the milk sugar in that way but the right answer here is black to stack up to the milk sugar number 23 a carbohydrates known commonly as inverted sugar is a fructose b sucrose c glucose d lac tools so the right answer here is sucrose i need to waste time on such easy questions number 24 a homopolysaccharide among the following is a hyperin b hyaluronic acid c dematin sulfate c cellulose then take it again a hormone polysaccharides among the following is a hypovolene b hyaluronic acid the the right answer here is the cellulose 25 a heteropolysaccharides among the following is a inulin b cellulose c hyperine the deck string let me change the question again a a heteropolysaccharide among the following is a inulin b cellulose c hypervenom d dextrin so the right answer here is c hyperin26 the predominant form of glucose in solution is a a cyclic form b hydrated a acyclic form c glucose d gluco pyranose the predominant form of glucose in solution is which of the following so the right answer in this question would be d gluco pyramus number 27 optica absolution isomerism is denoted by a d and l b d and one method c plus a negative sign method d any of this which are the following we we identify or we denote an optical isomerism situation the right answer here is c plus minus 28 an l isomer of monosaccharide formed in human body a l fructose b l electrodes c l zydos d x sorry d l zelulus an l isomer of monosaccharides formed in human body is a l fructose l electrodes l xylose and l z so which are the following upon the option you give the right answer so the right answer here number 28 is d l with 29 a pencil is found in nucleotides is a d rebels b l rebels c d ribolus d l rebuildus a pencils as a five carbon sugar found in nucleotides is which are the following it's right on size a the following causes level rotation a d fructose b l glucose c l we both d all of this so which i want this option will cause uh level rotation in the right answer just know that whatever molecule has the l the l notation it obviously causes rotation and this d fructose also causes some degree of the momentum so the right answer is d number 31 in straight chain structure of d glucose o h group is present on left hand side of carbon atom number what so if you have to draw the structure of glucose from one to six having a six carbon chain uh if you look at it you find that do you if you draw a diagonal you can get the answer this question is very simple question so the right answer to this question is three so on carbon 3 you will see you will see uh where the o h is on the other side like it will be something like this whatever on this right hand side you will see hydrogen why on the other side you will see an o h group something like that the android series will be going up and going down number 32 in a straight chain structure of d rebels hydroxy or oh group is present on the right hand side of carbon atom number let me take it again a straight chain structure of derivatives so this is a divorce structure o h group is present on the right hand side of carbon atom number a 2 b 3 c 4 d all of this so all you have to do take a pen and draw out a d we both structure and you usually get your answer so do i answer this question that 2 is d of the bone you find an o h at the right-hand side at this various positions number 23 the carbon atom which becomes asymmetrical when the straight chain form of monosaccharides changes into ring form is known as a monomeric carbon atom b epimeric carbon atom c isomeric carbon atom d none of this the carbon atom which becomes asymmetrical when the straight chain form of a motorcycle changes into ring form and known as to the right answer here is the anomaly carbon atom you got it correctly method to four in a d glucopyranus oh groups projecting below the plane of the ring are attached to carbon atoms a 1 2 and 3 b 1 2 and 4 c 2 3 and 4 d 1 2 and five so what they actually need here then like if you draw a d parallels which is something just something like this sorry another very clear diagram which looks uh something like this yeah so you know you have some projections downwards downwards downwards here here you have your your oakley carbon for your oxygen side so what they are actually here is that on which of these various positions which are down here will you find o h below so i was asking you so the right answer is b one one that is a one two and four positions number 35 in gluco paranos the anomeric carbon is a carbon 1b carbon 2 c carbon 5 d carbon six and gluco power now i think the glucose with this carbon chain so here is a so i was saying uh panel is a subscriber chain it is not necessarily a cis carbon chain because it doesn't have cis carbon in the chain but it's actually uh a a shape with six sides so we have a carbon here you have an oxygen here you have a carbon here yeah i'm going to come on here get one in the carbon here yeah right now carbon here so it's like this but this is an oxygen so it's not similarly this is carbon okay because the other carbon we found somewhere here which should be showing ch ch2 oh hey like that 136 the smallest right having fire nose wing structure is the smallest circle right having finals wing structure is a victro's b ribose c glucose the fructose which are the following stimuli to answer this question if you want to answer something like this you should always think of which are the following has smallest possible uh brain structure to the right answer for this question would be b ribose methyl 7 the specific rotation of alpha d glucopyranus is a plus 19 degrees b plus 55. 2 degrees c plus 92 degrees d 112 plus 112 degrees so what do you think is the answer so what did you have seen you like yeah take for instance you you have a mixture of both alpha d glycopyranose and uh and beta d like copernicus so they're both in the same solution or on the same mixture so if you have to find the uh the the angle or that specific rotation so that's what they are asking you in this particular equation and the right assessment of this equation is d 112 degrees for the alpha d like compounds to the specific rotation of beta d glycopyranus is a plus 19 degrees b 52. 5 degrees c 92 degrees d 112 degrees so the right answer this question is 19 degrees in some texts you may see uh maybe some text 18 18 uh eighteen 0.
